#93 · Greedy · Intermediate · 75 XP · about 14 min
meetings is a list of [start, end] times for meetings that all want the same room. Two meetings clash if their times overlap, but a meeting that ends at time t does not clash with one that starts at t.
Write max_meetings(meetings) that returns the largest number of meetings the room can host with no clashes.
max_meetings([[1, 4], [3, 5], [0, 6], [5, 7], [8, 9]]) # returns 3 max_meetings([[1, 10], [2, 3], [4, 5]]) # returns 2 max_meetings([[1, 3], [3, 6], [6, 8]]) # returns 3
In the second example the long meeting from 1 to 10 blocks both short ones, so it is better to drop it and keep the other two.
0 <= len(meetings) <= 100000 <= start < end <= 10**9Ready?
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